A trigonometric proof of the pythagorean theorem

by @ulaulaman via @MathUpdate http://t.co/LJX8gSX7xf

\[\alpha + \beta = \frac{\pi}{2}\] \[\sin (\alpha + \beta) = \sin \frac{\pi}{2}\] \[\sin \alpha \cdot \cos \beta + \sin \beta \cdot \cos \alpha = 1\] \[\frac{a}{c} \cdot \frac{a}{c} + \frac{b}{c} \cdot \frac{b}{c} = 1\] \[\frac{a^2}{c^2} + \frac{b^2}{c^2} = 1\]

\[a^2 + b^2 = c^2\]

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via @MathUpdate